Ask a New Question

Question

Find the indefinite integral.
∫xe^-4xdx
10 years ago

Answers

Steve
use integration by parts. Let

u = x, du=dx
v = e^-4x dx, v = -1/4 e^-4x

∫ udv = uv - ∫v du
so,

∫(x)(e^-4x dx0 = -1/4 xe^-4x + 1/4 ∫e^-4x dx
= -1/4 xe^-4x - 1/16 e^-4x
= -1/16 e^-4x (4x+1) + C
10 years ago

Related Questions

find the indefinite integral of (1/x)*(e^(-2log[ 3,x])) dx where 3 is base of the log i ca... find indefinite integral of (e^-x)-(1)/(e^-x+(x)^2 dx find indefinite integral ((e^-x)-(1))/((e^-x)+(x)) Find the indefinite integral. x^2(5 x^3 + 9)^3 dx Find the indefinite integral. (e^(4 x) + e^(-5 x)) dx Find Indefinite Integral of dx/(x(x^4+1)). I think that Im complicating it too much. I moved the dx... Find the indefinite integral of x^4/1-x^5dx. so far, I have these steps: ∫ f'(x)dx = ∫ x^4/1-x^5... Find the indefinite integral of (1-sqrtx)/(1+sqrtx)dx I just worked completely through this probl... Find the indefinite integral. ∫ x^2(1-x)^6 dx I am so lost on this. I let u=1-x so du=-dx.... Find the indefinite integral in two ways. ∫(2x-1)^2 dx The first way I used was using the powe...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use