Question
Find the indefinite integral in two ways.
∫(2x-1)^2 dx
The first way I used was using the power rule and chain rule with substitution.
Let u = 2x - 1
du = 2 dx
(1/2)∫ u^2 du
(Applying power rule)
(1/2) * (u^3/3) + C
=(2x-1)^3/6 + C
What would be another way of finding the indefinite integral??
∫(2x-1)^2 dx
The first way I used was using the power rule and chain rule with substitution.
Let u = 2x - 1
du = 2 dx
(1/2)∫ u^2 du
(Applying power rule)
(1/2) * (u^3/3) + C
=(2x-1)^3/6 + C
What would be another way of finding the indefinite integral??
Answers
Just expand the polynomial and integrate all the terms:
4x^2-4x+1 dx
4x^2-4x+1 dx
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