Asked by Ray
Find the indefinite integral in two ways.
∫(2x-1)^2 dx
The first way I used was using the power rule and chain rule with substitution.
Let u = 2x - 1
du = 2 dx
(1/2)∫ u^2 du
(Applying power rule)
(1/2) * (u^3/3) + C
=(2x-1)^3/6 + C
What would be another way of finding the indefinite integral??
∫(2x-1)^2 dx
The first way I used was using the power rule and chain rule with substitution.
Let u = 2x - 1
du = 2 dx
(1/2)∫ u^2 du
(Applying power rule)
(1/2) * (u^3/3) + C
=(2x-1)^3/6 + C
What would be another way of finding the indefinite integral??
Answers
Answered by
Steve
Just expand the polynomial and integrate all the terms:
4x^2-4x+1 dx
4x^2-4x+1 dx
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.