Asked by Adam
A voltaic cell is based on the following two half reactions:
Fe2+(aq) + 2 e¯ ---> Fe(s); Eo = -0.44 V
Cu2+(aq) + 2 e¯ ---> Cu(s); Eo = +0.34 V
When [Cu2+] = 0.0500 M, Ecell = + 0.80 V.
What is the [Fe2+] for these conditions?
Fe2+(aq) + 2 e¯ ---> Fe(s); Eo = -0.44 V
Cu2+(aq) + 2 e¯ ---> Cu(s); Eo = +0.34 V
When [Cu2+] = 0.0500 M, Ecell = + 0.80 V.
What is the [Fe2+] for these conditions?
Answers
Answered by
DrBob222
See your(?) post above.
http://www.jiskha.com/display.cgi?id=1309009417
http://www.jiskha.com/display.cgi?id=1309009417
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