Question
The voltaic cell described by the balanced chemical reaction has a standard emf of 4.05 V. Calculate the equilibrium constant (Kc) for the reaction at 25 oC. Round your answer to 3 significant figures.
F2(g) + Mn(s) → 2F-(aq) + Mn2+(aq)
Mn2+/Mn -1.18
F2/F- +2.87
0 °C = 273.15 K
R = 8.314 J/(K x mol)
Faraday's Constant
96485 C/mol
F2(g) + Mn(s) → 2F-(aq) + Mn2+(aq)
Mn2+/Mn -1.18
F2/F- +2.87
0 °C = 273.15 K
R = 8.314 J/(K x mol)
Faraday's Constant
96485 C/mol
Answers
nEF = RTlnK
I tried doing that but the value was so high that I wanted to compare answers with something you would get DrBob222. My answer was something e^136
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