Question

One half-cell in a voltaic cell is constructed from a silver wire electrode in a .25 M solution of AgNO3 . The other half-cell consists of a zinc electrode in a .001 M solution of Zn(NO3)2. Calculate the cell potential

I have no idea and am so stressed, Help please

Answer 1

Look up reduction potentials for these two.
E = Eo - (0.05916/n)*log[(red)/(ox)] for Ag.
E = Eo - etc etc for Zn.

Reverse one of the Eo values(change sign, too) and add to the other. Do this in such a fashion that the Ecell = + value volts. That gives you the Eocell.