Asked by Anonymous
One half-cell in a voltaic cell is constructed from a silver wire electrode in a .25 M solution of AgNO3 . The other half-cell consists of a zinc electrode in a .001 M solution of Zn(NO3)2. Calculate the cell potential
I have no idea and am so stressed, Help please
I have no idea and am so stressed, Help please
Answers
Answered by
DrBob222
Look up reduction potentials for these two.
E = Eo - (0.05916/n)*log[(red)/(ox)] for Ag.
E = Eo - etc etc for Zn.
Reverse one of the Eo values(change sign, too) and add to the other. Do this in such a fashion that the Ecell = + value volts. That gives you the Eocell.
E = Eo - (0.05916/n)*log[(red)/(ox)] for Ag.
E = Eo - etc etc for Zn.
Reverse one of the Eo values(change sign, too) and add to the other. Do this in such a fashion that the Ecell = + value volts. That gives you the Eocell.
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