Asked by Mikah
In the voltaic cell that is represented as: Cu | Cu2+ || Fe | Fe2+.
The only anion in solution in the cells and salt bridge is the nitrate ion.
The directions the electron external circuit and NO3- flow in the salt bridge circuit will be:
*electron flow is Fe to Cu
*electron flow is Cu to Fe
*electron flow is cathode to anode.
*electron flow is anode to cathode.
*ion flow is NO3- ions to the cell with the anode
*ion flow is NO3- ions to the cell with the cathode
The only anion in solution in the cells and salt bridge is the nitrate ion.
The directions the electron external circuit and NO3- flow in the salt bridge circuit will be:
*electron flow is Fe to Cu
*electron flow is Cu to Fe
*electron flow is cathode to anode.
*electron flow is anode to cathode.
*ion flow is NO3- ions to the cell with the anode
*ion flow is NO3- ions to the cell with the cathode
Answers
Answered by
DrBob222
The rxn is
Fe + Cu^2+ ==> Cu + Fe^2+
so the electrons flow from Fe to Cu^2+. The anode is where oxidation occurs.
Since the Fe is going into solution and the Cu^2+ is coming out of solution, the Cu side has too many nitrate ions.
Fe + Cu^2+ ==> Cu + Fe^2+
so the electrons flow from Fe to Cu^2+. The anode is where oxidation occurs.
Since the Fe is going into solution and the Cu^2+ is coming out of solution, the Cu side has too many nitrate ions.
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