Asked by grace
A flat stone is thrown horizontally across a frozen lake. If the stone decelerates at 2.5 meter per second squared, what is the coefficient of friction between the stone and the ice?take g equals 10 meter per second
Answers
Answered by
Damon
I did this already
mu m g = m a = 2.5 m
mu = 2.5/g = 2.5/10 = 0.25
mu m g = m a = 2.5 m
mu = 2.5/g = 2.5/10 = 0.25
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