Question

A baseball is thrown horizontally from the top of a cliff 50 meters up. The initial velocity of the ball is 10 m/s. How far from the base of the cliff will the ball land?
how long to fall 50 meters?

d = 4.9 t^2
t = sqrt(50/4.9) = 3.19 seconds
so how far did it go horizontally?
d = u t = 10 * 3.19
= 31.9 meters

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