Asked by Abdelaziz
A 2.3kg stone is thrown from ground directly upward. the maximum height reached by the stone is 45m. Neglecting air resistance,
a) with which initial speed was the stone thrown?
b)what is the flight time of the stone until it hits the ground again?
c)what is the acceleration of the stone at the top point?
d) what is the net force acting on the stone during its free fall>
a) with which initial speed was the stone thrown?
b)what is the flight time of the stone until it hits the ground again?
c)what is the acceleration of the stone at the top point?
d) what is the net force acting on the stone during its free fall>
Answers
Answered by
Steve
Just drag out your standard formulas of motion:
a) v = √(2gs)
b) vt - 1/2 gt^2 = 0
c) -g
d) F=mg
a) v = √(2gs)
b) vt - 1/2 gt^2 = 0
c) -g
d) F=mg
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