A stone is thrown in the air with an initial velocity of 50 m/s at 37 degrees to the horizontal. Find the total time the ball is in the air. What would be the total distance traveled?

Answer 1

Vo = 50m/s[37o]
Xo = 50*cos37 = 39.93 m/s.
Yo = 50*sin37 = 30.09 m/s.

Tr = (Y-Yo)/g = (0-30.09)/-9.8 = 3.07 s
= Rise time.

Tf = Tr = 3.07 s. = Fall time.

T = Tr+Tf = 3.07 + 3.07 = 6.14 s. = Time
in air.

d = Xo*T = 39.93m/s * 6.14s = 245.2 m.
= Total dist. traveled.