Asked by Vinny
0.255 g sample of H2C2O4 required 25.70 mL of NaOH to neutralize, what would you report as the molarity of NaOH solution? the reaction is as follows:
H2C2O4(aq) +2 NaOH (aq) -> Na2C2O4(aq) +2 HOH (l)
H2C2O4(aq) +2 NaOH (aq) -> Na2C2O4(aq) +2 HOH (l)
Answers
Answered by
DrBob222
moles H2C2O4 = grams/molar mass = ??
Using the coefficients in the balanced equation, convert moles H2C2O4 to moles NaOH. That will be ??moles H2C2O4 x (2 moles NaOH/1 mole H2C2O4) = ??moles H2C2O4 x 2 = xx moles NaOH.
Then M NaOH = moles NaOH/L NaOH, and round to the appropriate number of significant figures.
Using the coefficients in the balanced equation, convert moles H2C2O4 to moles NaOH. That will be ??moles H2C2O4 x (2 moles NaOH/1 mole H2C2O4) = ??moles H2C2O4 x 2 = xx moles NaOH.
Then M NaOH = moles NaOH/L NaOH, and round to the appropriate number of significant figures.
Answered by
Vinny
.220 mol per liter
Answered by
DrBob222
I agree.
Answered by
Vinny
Thank you!
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