Asked by Donnie
H2C2O4(aq) + 2 NaOH(aq) → Na2C2O4(aq) + 2 H2O(l)
If I use 0.025 moles of NaOH to neutralize the Oxalic acid, how many moles of Oxalic acid are there?
If I use 0.025 moles of NaOH to neutralize the Oxalic acid, how many moles of Oxalic acid are there?
Answers
Answered by
DrBob222
0.025 mols NaOH = 1/2 * 0.025 mols H2C2O4
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