Asked by Anonymous
The height h in feet of a baseball after t seconds is given by h = -16t2 + 88t + 3. At what values of t is the height of the baseball 75 feet?
Answers
Answered by
bobpursley
75=-16t^2+88t+3
put in standard form.
16t^2 -88t+72=0
2t^2-11t+9=0
(2t -9)(t-1)=0
t= 4.5, 1
put in standard form.
16t^2 -88t+72=0
2t^2-11t+9=0
(2t -9)(t-1)=0
t= 4.5, 1
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