Asked by Kevin Chau
                The height h (in feet) of an underhand volleyball serve can be modeled by h=−16t2+30t+4, where t is the time in seconds. After how many seconds is the ball 16 feet above the ground? Round your answers to the nearest tenth.
The ball is 16 feet above the ground after about
_______
seconds and after about
__________
seconds.
            
        The ball is 16 feet above the ground after about
_______
seconds and after about
__________
seconds.
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