Question

θhe height h in feet of a car above the exit ramp of an amusement park′s free-fall ride can be modled by the equation h=−16t<E> 6<E>+s where t is the time in seconds after the car drops s is the starting height of the car in feet.

How high above the car′s exit ramp should the ride′s designer start the drop in order for the riders to experience free-fall for at least 3 seconds?

Answer 1

I don't know what h=−16t<E> 6<E>+s is supposed to say, but I know that

h = -16t^2 is the relation between t seconds and the distance fallen in feet

Since we just want to find the distance, let's use

h = 16t^2
when t = 3
h = 16(9) = 144 feet

If this is not what you want, then correct your typing.

Answer 2

If you mean h(t) = s - 16t^2 then we need s so that

s-16*9 = 0
s = 144 ft