Asked by mathman
The height h, in feet, of a ball above the ground t seconds after being thrown upward with a velocity of 48 ft/s is given by . After how many seconds will the ball be 35ft above the ground?
Answers
Answered by
Adam F
height = time * 48ft/s
35ft = time * 48ft/s
35ft/(48ft/s) = time
time = 0.72917 seconds
35ft = time * 48ft/s
35ft/(48ft/s) = time
time = 0.72917 seconds
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