# Plane A left Vancouver for Winnipeg, a distance of 2232 km, travelling at an average speed of 560km/h. At the same time, Plane B left Winnipeg for Vancouver travelling at an average spped of 430km /h. how long after take-off did the planes pass each other?

13 years ago

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9 years ago

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10 months ago

## To find out how long after take-off the planes passed each other, we can use the concept of relative speed.

The relative speed between the two planes is the sum of their individual speeds. In this case, Plane A is moving at 560 km/h, while Plane B is moving at 430 km/h. Therefore, the relative speed between the two planes is 560 km/h + 430 km/h = 990 km/h.

Now, we need to determine how long it takes for the two planes to cover the total distance between Vancouver and Winnipeg, which is 2232 km.

Using the formula: Time = Distance / Speed, we can calculate the time it will take for Plane A to travel from Vancouver to the meeting point with Plane B.

Time taken by Plane A = Distance / Speed = 2232 km / 560 km/h = 3.97 hours (rounded to two decimal places)

Similarly, we can calculate the time taken by Plane B to travel from Winnipeg to the meeting point with Plane A.

Time taken by Plane B = Distance / Speed = 2232 km / 430 km/h = 5.19 hours (rounded to two decimal places)

Since both planes started at the same time, the total time it takes for the planes to pass each other will be the time it takes for either plane to reach the meeting point.

Hence, the planes will pass each other approximately 3.97 hours after take-off.