Asked by Chris
find the point on the graph of y=x^2 where the tangent line is parallel to the line 2x-y=2
Answers
Answered by
Henry
Y = X^2. 2X - Y = 2.
m = -A/B = -2 / -1 = 2 = Slope.
m2 = Y' = 2X = Slope of parabola.
Y' = 2X = 2,
2X = 2,
X = 1.
Y = X^2
Y = 1^2 = 1.
P(1, 1).
If you graph the parabola, you can use
the following points:
(-2,4), (-1,1), V(0,0), (1,1),(2,4).
m = -A/B = -2 / -1 = 2 = Slope.
m2 = Y' = 2X = Slope of parabola.
Y' = 2X = 2,
2X = 2,
X = 1.
Y = X^2
Y = 1^2 = 1.
P(1, 1).
If you graph the parabola, you can use
the following points:
(-2,4), (-1,1), V(0,0), (1,1),(2,4).
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.