Question
find the point on the graph of y=x^2 where the tangent line is parallel to the line 2x-y=2
Answers
Henry
Y = X^2. 2X - Y = 2.
m = -A/B = -2 / -1 = 2 = Slope.
m2 = Y' = 2X = Slope of parabola.
Y' = 2X = 2,
2X = 2,
X = 1.
Y = X^2
Y = 1^2 = 1.
P(1, 1).
If you graph the parabola, you can use
the following points:
(-2,4), (-1,1), V(0,0), (1,1),(2,4).
m = -A/B = -2 / -1 = 2 = Slope.
m2 = Y' = 2X = Slope of parabola.
Y' = 2X = 2,
2X = 2,
X = 1.
Y = X^2
Y = 1^2 = 1.
P(1, 1).
If you graph the parabola, you can use
the following points:
(-2,4), (-1,1), V(0,0), (1,1),(2,4).