Asked by Roberto DX
Find the point on the graph of f(x)=√x that is closest to the value (4,0).
(differentiate the square of the distance from a point (x,√x) on the graph of f to the point (4,0).)
(differentiate the square of the distance from a point (x,√x) on the graph of f to the point (4,0).)
Answers
Answered by
MathMate
Square of distance from (4,0)
D(x)= ((x-4)^2+x)
For minimum, D'(x)=0
2(x-4)+1=0
x=7/2
D(x)= ((x-4)^2+x)
For minimum, D'(x)=0
2(x-4)+1=0
x=7/2
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