Question

1) Find the point on the graph of y=x^2 where the cube has slope 5/2

2) Find the point on the graph of y=x^2 where the tangent line is parallel to the line -4x+3y=3

Answer 1

The first question has a type point should be on the curve of the graph not the cube

Answer 2

since the slope anywere is just y'=2x, you want to find where

2x = 5/2
x = 5/4
So, the desired point is (5/4,25/16)

For the other one, figure the slope of the tangent line, and then follow the same steps.