Asked by tyler

Equation: 4NH3(g) + 5O2(g) -> 4NO(g) + 6H2O(g)
question: What volume of NH3 is needed to react with 71.6 liters of oxygen?

14 years ago

Answered by DrBob222

Use the coefficients to convert L oxygen to L NH3.
71.6 L O2 x (4 moles NH3/5 moles O2) = 71.6 x (4/5) = ??

14 years ago

Answered by TJ

thanks Dr. Bob

14 years ago

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