Question

Given:

Equation #1: 4NH3(g) + 5O2(g) = 4NO(g) + 6H2O; ΔH of reaction = -1170 kJ

Equation #2: 4NH3(g) + 3O2(g) = 2N2(g) + 6H2O; ΔH of reaction = -1530 kJ

Then what is the ΔH of reaction for: N2(g) + O2(g) = 2NO(g)? Enter a numerical value below and be sure to include a minus sign if needed. The error interval is +/- 5 kJ. The units are kJ.

Answer 1

Add equation 1 to the reverse of equation 2, then divide the final equation by 2.
When reversing an equation change the sign of dH. When dividing an equation by 2 divide dH by 2. When adding equations add dH values for each.

Answer 2

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