Asked by Anonymous
4NH3(g) + 5O2(g) → 4NO (g) + 6H2O(g)
Using the above equation, at STP, when 0.675 L of ammonia burns, what volume of water vapor will be formed?
Using the above equation, at STP, when 0.675 L of ammonia burns, what volume of water vapor will be formed?
Answers
Answered by
oobleck
H2O:NH3 = 6:4
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