To determine the number of moles of NO (nitric oxide) produced, you need to use the balanced chemical equation and the given quantities of reactants.
1. Calculate the number of moles of NH3:
To find the number of moles, divide the given mass by the molar mass of NH3.
Molar mass of NH3 = 14.01 g/mol (N) + 3(1.01 g/mol) (H) = 17.03 g/mol
Number of moles of NH3 = 170 g / 17.03 g/mol = 9.99 mol (approx.)
2. Calculate the number of moles of O2:
Similarly, divide the given mass by the molar mass of O2.
Molar mass of O2 = 2(16.00 g/mol) = 32.00 g/mol
Number of moles of O2 = 384 g / 32.00 g/mol = 12.00 mol
3. Determine the limiting reactant:
The limiting reactant is the reactant that is completely consumed and determines the amount of product that can be formed. To find it, compare the moles of NH3 and O2. According to the balanced equation, the mole ratio between NH3 and O2 is 4:5. Therefore, the ratio of moles is also 4:5. Since the ratio of NH3 to O2 is smaller than this, NH3 is the limiting reactant.
4. Calculate the moles of NO produced:
Using the mole ratio from the balanced equation, the ratio of NH3 to NO is 4:4. Therefore, the moles of NO produced are the same as the moles of NH3, which is 9.99 mol.
5. Calculate the grams of NO produced:
To find the grams of NO produced, multiply the moles of NO by the molar mass of NO.
Molar mass of NO = 14.01 g/mol (N) + 16.00 g/mol (O) = 30.01 g/mol
Grams of NO produced = 9.99 mol * 30.01 g/mol = 299.70 g (approx.)
Therefore, approximately 9.99 moles of NO and 299.70 grams of NO will be produced.