4NH3 + 5O2 --> 4NO + 6H2O

Question

170g of ammonia (NH3) are allowed to react with 384g of O2.

how many moles of NO is produced? and also how many grams of NO will be produced?

Answer 1

figure the moles of NH3 in 170g.
now figure the moles of O2 in 384g

if you have 5/4 more moles of O2 than NH3, then NH3 is the limiting reageant. Moles NO=molesNH3*
if you have less than 5/4 moles of O2, then O2 is limiting. Moles NO = 4/5 moles of O2 reacted.