Asked by Ana
Ammonia and oxygen react to form nitrogen and water.
4NH3(g)+3 O2(g)-2N2(g)+6H2O(g)
a.How many grams of O2 are needed to react with 8.00 mol NH3?
8.00 mol NH3 x42.094/4 mol NH3 x32.00 O2/1 mol O2=269gO2
4NH3(g)+3 O2(g)-2N2(g)+6H2O(g)
a.How many grams of O2 are needed to react with 8.00 mol NH3?
8.00 mol NH3 x42.094/4 mol NH3 x32.00 O2/1 mol O2=269gO2
Answers
Answered by
Ana
Ammonia and oxygen react to form nitrogen and water.
4NH3(g)+3 O2(g)-2N2(g)+6H2O(g)
a.How many grams of O2 are needed to react with 8.00 mol NH3?
8.00 mol NH3 x42.094/4 mol NH3 x32.00 O2/1 mol O2=269gO2
4NH3(g)+3 O2(g)-2N2(g)+6H2O(g)
a.How many grams of O2 are needed to react with 8.00 mol NH3?
8.00 mol NH3 x42.094/4 mol NH3 x32.00 O2/1 mol O2=269gO2
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