Ask a New Question
Search
Asked by
Anonymous
4NH3+5O2)4NO+6H2O
H2+1/2 O2=H2O Dalta H=-286
1/2 N2+1/2 O2=NO Dalta H=90
1/2 N2+3/2 O2=NH3 Dalta H =46
Answers
Answers
Answered by
DrBob222
I see a bunch of equations and numbers but no question. What is the question and what are the units for dH?
Related Questions
Related
4NH3 + 7O2 = 4NO2 + 6H2O HHOW MANY MOLES OF AMMONIA WILL BE REQUIRED TO PRODUCE 10.0 MOLES OF WATER?...
4Nh3(g) +3O2(g)=2N2(g)+6H2O(g) has kp=2.1x10^6 atm. Initial concentration of NH3=2.00 atm, and N2=1....
4NH3+5O2--->4NO+6H2O determine the amount of oxygen needed to produce 1.2x10^4mol of nitrogen mono...
4NH3 + 5O2 → 4NO + 6H2O 2NO + O2 → 2NO2 3NO2 + H2O → 2HNO3 + NO In this process, the NO made...
4NH3 + 5O2 --> 4NO + 6H2O 170g of ammonia (NH3) are allowed to react with 384g of O2. how man...
Given that 4NH3+5O2-4NO+6H2O ΔH= -906kJ. What is the Enthalpy change for NO +3/2H2O - NH3 +5/2 O2
4NH3(g) +3O2(g) =2N2(g) +6H2O(l) 131.0 g of NH3 is mixed with 221.2 g of O2 and allowed to react....
4NH3(g) + 3O2(g)= 2N2(g)+ 6H2O(l)
4NH3(g)+502(g):4NO(g)+6H2O(1)
4NH3 +5O2 → 4NO +6H2O Using the equation above,what is the limiting reagent and theoretical yield i...