4NH3(g) + 3O2(g)= 2N2(g)+ 6H2O(l)

4NH3 + 7O2 = 4NO2 + 6H2O HHOW MANY MOLES OF AMMONIA WILL BE REQUIRED TO PRODUCE 10.0 MOLES OF WATER?...

4Nh3(g) +3O2(g)=2N2(g)+6H2O(g) has kp=2.1x10^6 atm. Initial concentration of NH3=2.00 atm, and N2=1....

4NH3+5O2--->4NO+6H2O determine the amount of oxygen needed to produce 1.2x10^4mol of nitrogen mono...

4NH3 + 5O2 → 4NO + 6H2O 2NO + O2 → 2NO2 3NO2 + H2O → 2HNO3 + NO In this process, the NO made...

4NH3 + 5O2 --> 4NO + 6H2O 170g of ammonia (NH3) are allowed to react with 384g of O2. how man...

Given that 4NH3+5O2-4NO+6H2O ΔH= -906kJ. What is the Enthalpy change for NO +3/2H2O - NH3 +5/2 O2

4NH3(g) +3O2(g) =2N2(g) +6H2O(l) 131.0 g of NH3 is mixed with 221.2 g of O2 and allowed to react....

4NH3+5O2)4NO+6H2O H2+1/2 O2=H2O Dalta H=-286 1/2 N2+1/2 O2=NO Dalta H=90 1/2 N2+3/2 O2=NH3 Dalta...

4NH3(g)+502(g):4NO(g)+6H2O(1)

4NH3 +5O2 → 4NO +6H2O Using the equation above,what is the limiting reagent and theoretical yield i...

Asked by YASİR SATLEH