Asked by Jake

Please find the integral for:

(2^(-1/t))/(t^2)

Thank you very much

14 years ago

Answered by agrin04

|2^(-1/t)*(1/t^2) d(-1/t)/(1/t^2)= |2^(-1/t) d(-1/t) = 2^(-1/t)/ln2 + const

14 years ago

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