Asked by Hannah

Find: the integral (x^2/4 - 4) dx

I know that the answer is x^3/12 -4 +c but I do not know how to get this
Answered by Hannah
o I think I know. Is it because you add 1 to the x^2 which is x^3 and the inverse 1/3 you multiply by 4 to get 12
Answered by Damon
(1/4) integral(x^2-16) dx

= (1/4) [ integral x^2 dx -integral dx]

= (1/4 [ x^3/3 - 16 x + C]

= x^3/12 - 4 x + c
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