Asked by tiff

Find F'(x) given F(x)= integral(upper 3x)(lower-3x)s^2 ds

Answer choices
A. F'(x)=2187x^6
B. F'(x)=54x^2
C. F'(x)=24x^2
D. F'(x)=729x^6
Answered by oobleck
that would be (3x)^2 * (3) - (-3x)^2 * (-3)
Answered by tiff
so does that mean it would be A,B,C,or D????
Answered by tiff
@oobleck how did you get that?
Answered by oobleck
Recall that if F(x) = ∫[u,v] f(s) ds
then
F'(x) = f(v) * v' - f(u) * u'
This is just the Chain Rule in reverse
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