how would i find the integral of sin (2t+1)/cos^2(2t+1) dt

Answer 1

let u = (2t+1)
du = 2 dt so dt = .5 du
so
.5 integral du sin u/cos^2u

try 1/cos u
d/du (1/cos u) = -sin u/cos^2 u

You can take it from there :)