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I have to find the integral of

(e^3lnx + e^3x)dx. Can someone help me?

2 answers

Is that (e^3)(lnx) + (e^3)(x) or
e^(3lnx) + e^(3x)?

Assuming the latter, since it's slightly more interesting than e^3*(lnx + x)

e^(3lnx)dx = x^3 dx
e^(3x)dx = 1/3 e^u du where u = 3x

That should be easy
Would the answer be (x^4)/4 + (e^3x)/3 + C?
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