Asked by Julia

How many kJ will be released as 575 g of steam at 176 degrees celsius are changed into ice at -75 degrees celsius?
Answered by DrBob222
q1 = heat released to move steam from 176 C to 100 C.
q1 = mass steam x specific heat x (Tfinal-Tinitial) where Tinitial = 176 and Tfinal = 100.

q2 = heat released to condense steam
@ 100 C to liquid water @ 100 C.
q2 = mass steam x heat vaporization

q3 = heat released to move temperature liquid water from 100 C to 0 C.
q3 = mass water x specific heat water x (Tfinal-Tinitial).

q4 = heat released to change liquid water @ 0 C to solid water @ 0 C.
q4 = mass water x heat fusion.

q5 = heat released to move solid water (ice) from zero C to -75 C.
q5 = mass ice x specific heat ice x (Tfinal-Tinitial).

Total Q = q1 + q2 + q3 + q4 + q5, then change J to kJ.
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