Asked by Elizabeth
1. A 3kg box is released from the top of a 20° inclined plane. If the length of the inclined plane is 10m long, and a frictional force of 10N opposes the motion of the ball, Determine the speed of the ball when the ball reaches the bottom of the plane.
Answers
Answered by
oobleck
effective weight of box = 3*9.81 cos20° = 27.655
net downward acceleration = 17.655
v = √(2as) = √(2*17.655*10) = 18.79 m/s
net downward acceleration = 17.655
v = √(2as) = √(2*17.655*10) = 18.79 m/s
Answered by
Dave Ningi
Help me to find the speed of the ball reaches the bottom of the plane
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