Asked by Abby
A 2.7 kg box is released on a horizontal surface with an initial speed of 2.9 m/s. It moves on the surface with an acceleration of .27 m/s squared. Calculate the kinetic friction force on the box. The coefficent of the kinetic force is .156.
Answers
Answered by
drwls
The acceleration is negative since the surface is horizontal and friction is the only horizontal force acting.
Compute the friction force from
F = m a
That gives F = 0.73 Newtons
There is another way to compute the friction force, and it gives a different result.
F = (kinetic coefficient) * M g
Your problem is inconsistent and overspecified. The initial speed makes no difference.
Compute the friction force from
F = m a
That gives F = 0.73 Newtons
There is another way to compute the friction force, and it gives a different result.
F = (kinetic coefficient) * M g
Your problem is inconsistent and overspecified. The initial speed makes no difference.
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