Use F = m a, along the direction of motion. The net force pusing the box downhill is
M g sin39 - Ff = M a
Solve for Ff, the friction force.
Please do not put your grade level as the subject.
A 16.0 kg box is released on a 39.0° incline and accelerates down the incline at 0.267 m/s2. Find the friction force impeding its motion
1 answer