Asked by Anonymous
A 16.0 kg box is released on a 39.0° incline and accelerates down the incline at 0.267 m/s2. Find the friction force impeding its motion
Answers
Answered by
drwls
Use F = m a, along the direction of motion. The net force pusing the box downhill is
M g sin39 - Ff = M a
Solve for Ff, the friction force.
Please do not put your grade level as the subject.
M g sin39 - Ff = M a
Solve for Ff, the friction force.
Please do not put your grade level as the subject.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.