Asked by Anonymous
"An alpha particle (a helium nucleus) is traveling along the positive x-axis at 1 250 m/s when it enters a cylindrical tube of radius 0.500 m centered on the x axis. Inside the tube is a uniform electric field of 4.50 X 10^-4 N/C pointing in the negative y direction. How far does the particle travel before hitting the tube wall? "
I know the answer is 0.849m I just don't understand how my teacher got that answer. Can someone please help "dumbify" it for me?
I know the answer is 0.849m I just don't understand how my teacher got that answer. Can someone please help "dumbify" it for me?
Answers
Answered by
drwls
Calculate the acceleration of the particle toward the tube wall, 2eE/m
e is the electron charge and m is the mass of an alpha particle, 4 Mp
The time it takes to move and hit the side wall will be given by
R = (a/2) t^2
Solve for t.
The distance travelled will be V*t
The distance 0.849 m seems suspiciously short to me. That is a very weak E-field.
a = 2*1.6*10^-19*4.5*10^-4/[4*1.67*10^-27) = 2.16*10^4 m/s^2
t = sqrt(2R/a) = 6.81*10^-3 s
X = distance traveled = V*t = 8.5 m
Unless I made a mistake somewhere, I disagree with the answer you "know" by a factor of ten
e is the electron charge and m is the mass of an alpha particle, 4 Mp
The time it takes to move and hit the side wall will be given by
R = (a/2) t^2
Solve for t.
The distance travelled will be V*t
The distance 0.849 m seems suspiciously short to me. That is a very weak E-field.
a = 2*1.6*10^-19*4.5*10^-4/[4*1.67*10^-27) = 2.16*10^4 m/s^2
t = sqrt(2R/a) = 6.81*10^-3 s
X = distance traveled = V*t = 8.5 m
Unless I made a mistake somewhere, I disagree with the answer you "know" by a factor of ten
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