Asked by Anonymous
Two alpha particles (helium nuclei), each consisting of two protons and two neu- trons, have an electrical potential energy of 6.08×10−19 J.
What is the distance between these par- ticles at this time? The Coulomb constant is 8.98755 × 109 N · m2/C2, the elemental charge is 1.6021 × 10−19 C, and the eration due to gravity is 9.8 m/s2.
Answer in units of m.
What is the distance between these par- ticles at this time? The Coulomb constant is 8.98755 × 109 N · m2/C2, the elemental charge is 1.6021 × 10−19 C, and the eration due to gravity is 9.8 m/s2.
Answer in units of m.
Answers
Answered by
bobpursley
Well, leave one particle alone, put the other at infinity (zero PE), and bring it to position d from the other. The work done must be the PE of the system.
Work=force*distance
= INTegral kqq/x^2 dx= -kqq/x over limits
= =kqq/inf - (-kqq/d)
or d= kqq/electricalPE
you have the numbers given, solve for d.
In my google search window, I entered..
((8.89E9)(1.60E-19)^2)/(6.08E-19)=
Now that is the distance. You do not need g except to ponder why it was given.
Work=force*distance
= INTegral kqq/x^2 dx= -kqq/x over limits
= =kqq/inf - (-kqq/d)
or d= kqq/electricalPE
you have the numbers given, solve for d.
In my google search window, I entered..
((8.89E9)(1.60E-19)^2)/(6.08E-19)=
Now that is the distance. You do not need g except to ponder why it was given.
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