Asked by brooke

An alpha particle (charge = +2.0e) is sent at high speed toward a gold nucleus (charge = +79e). What is the electric force acting on the alpha particle when the alpha particle is 1.7 multiplied by 10-14 m from the gold nucleus?
N

Answers

Answered by bobpursley
coulombs law...

F=kq1*q2/r^2
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions