Question

An alpha particle moving at a speed of 5.20x10^4 m/s enters a perpendicular magnetic field with a strength of 3.0 mT. The magnitude of the acceleration of the particle as it enters the magnetic field will be a.bcx10^d m/s^2 ?
a = q V B/m

You do the numbers.
q = 2 e
m = 4*(proton mass)

Related Questions

Q)1 : Alpha particles travel through a magnetic field of 0.360T and are deflected in an arc of 0.082... A charged particle with mass m, and a charge q, is moving through a perpendicular magnetic field of... A proton moving with a speed of 200 m/s enters perpendicular to the direction of the magnetic field...