Question
An alpha particle approaches a uranium nucleus as 1e6 m/s what is the closest this particle will get to the nucleus
how do you set this problem up? thanks!
how do you set this problem up? thanks!
Answers
bobpursley
set its original KEnergy equal to the PE at the closest point.
1/2 massalpha*1E12=kq1*q2/r
solve for r
1/2 massalpha*1E12=kq1*q2/r
solve for r
James
wait
but kqq/r2 is the equation for a force
not an energy
but kqq/r2 is the equation for a force
not an energy