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An alpha particle approaches a uranium nucleus as 1e6 m/s what is the closest this particle will get to the nucleus

how do you set this problem up? thanks!
15 years ago

Answers

bobpursley
set its original KEnergy equal to the PE at the closest point.


1/2 massalpha*1E12=kq1*q2/r
solve for r
15 years ago
James
wait
but kqq/r2 is the equation for a force
not an energy
15 years ago

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