Asked by melad
A 10.0-kg block is at rest on a horizontal floor. If you push horizontally on the 10.0-kg block with a force of 20.0 N, it just starts to move.
(a) What is the coefficient of static friction?
b) A 12.0-kg block is stacked on top of the 10.0-kg block. What is the magnitude F of the force, acting horizontally on the 10.0-kg block as before, that is required to make the two blocks start to move?
(a) What is the coefficient of static friction?
b) A 12.0-kg block is stacked on top of the 10.0-kg block. What is the magnitude F of the force, acting horizontally on the 10.0-kg block as before, that is required to make the two blocks start to move?
Answers
Answered by
Henry
Fb = 10kg * 9.8 = 98N = Force of block.
Fb = Fv = 98N,
a. Fh - u*Fv = 0,
20 - 98u = 0,
98u = 20,
u = 20 / 98 = 0.20.
b. Fb = (10 + 12)kg * 9.8 = 215.6N.
= Force of blocks.
Fv = Fb = 215.6N.
Fh - u*Fv = 0,
Fh = u*Fv = 0.2 * 215.6 = 43.1N = Force required to move the blocks.
Fb = Fv = 98N,
a. Fh - u*Fv = 0,
20 - 98u = 0,
98u = 20,
u = 20 / 98 = 0.20.
b. Fb = (10 + 12)kg * 9.8 = 215.6N.
= Force of blocks.
Fv = Fb = 215.6N.
Fh - u*Fv = 0,
Fh = u*Fv = 0.2 * 215.6 = 43.1N = Force required to move the blocks.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.