Asked by Tori carr

A 4 kg wooden block rest on a table. the coefficient of friction between the block and the table is .40. a 5kg mass is attached to the block by a horizontal string passed over a frictionless pulley of neglible mass what is the acceleration of the block when the 5 kg mass is released? what is the tension in the string during the acceleration?
Answered by Anonymous
Force applied =5kgx9.8= 49N
Force Against (friction)=4kgx9.8x.4=15.68

first to find the Acceleration...

49-15.69=Total Force= 33.32N

F=MA F/M=A 33.32/9(both blocks)= 3.702m/ss

Now for Tension..

9.8-3.702=6.098

6.098X5=30.49N=Tension
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