Question
A 32.0 kg block at rest on a horizontal frictionless table is connected to the wall via a spring with a spring constant k= 32.0 N/m. A 2.00E-2 kg bullet travelling with a speed of 5.500E+2 m/s embeds itself in the block. What is the amplitude of the resulting simple harmonic motion? Recall that the amplitude is the maximum displacement from equilibrium.
Answers
Chanz
m1v1 = (m1+m2)vf
1/2 (m1 + m2) vf^2 = 1/2 kx^2
solve for x
1/2 (m1 + m2) vf^2 = 1/2 kx^2
solve for x