Asked by Anonymous
find lim (2x+1+cos2x/22)
x->0
Give one sequence starting at x=0.1 to support your claim.
x->0
Give one sequence starting at x=0.1 to support your claim.
Answers
Answered by
Reiny
lim (2x+1+cos2x/22)
x->0
= (0+1+1/22)
= 23/22
x->0
= (0+1+1/22)
= 23/22
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