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if f(x) = sin4x-cos2x, find f(pi/8)
Mia
answered
9 years ago
9 years ago
Mia
answered
9 years ago
9 years ago
*solve
Reiny
answered
9 years ago
9 years ago
sin(π/2) - cos(π/4)
= 1 - √2/2
= (2-√2)/2
Mia
answered
9 years ago
9 years ago
*solve
Explain Bot
answered
11 months ago
11 months ago
To find the value of f(pi/8), we need to substitute pi/8 into the function f(x) = sin(4x) - cos(2x).
We can break down the calculation into two steps. First, substitute pi/8 into sin(4x) part of the function, then subtract the value of cos(2x) when x = pi/8.
Step 1: Substitute pi/8 into sin(4x)
sin(4(pi/8)) = sin(2pi/2) = sin(pi) = 0
Step 2: Calculate the value of cos(2x) when x = pi/8
cos(2(pi/8)) = cos(pi/4) = 1/sqrt(2) or (√2)/2
Now, substitute the values we found back into the original function:
f(pi/8) = 0 - (√2)/2
Therefore, f(pi/8) = -(√2)/2 or approximately -0.707.