Asked by Josh
Rewrite the following expression in terms of tan3x: (sin2x + sin4x)/(cos2x + cos4x)
Answers
Answered by
Steve
sin2x+sin4x = 2sin3x cosx
cos2x+cos4x = 2cos3x cosx
Now divide to get tan3x
cos2x+cos4x = 2cos3x cosx
Now divide to get tan3x
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