Asked by Raj
Find the value of cos2x=3/4.Find the two values of x.
0<x>pi(180)
0<x>pi(180)
Answers
Answered by
oobleck
see your previous post. You should be able to finish it off.
Check your answers to make sure they fit the original equation.
Check your answers to make sure they fit the original equation.
Answered by
Raj
Can you show how to do with inverse of cos?
Answered by
Reiny
Picking up from oobleck's
cosx = ±√(7/8) = ±0.935
depends on your calculator.
on mine (SHARP) I do the following.
2nd cos
.935
=
to get 20.77...
I have it said on degrees, (the DRG) key, so one answer is 20.77°
Of course using your CAST rule, you know that the cosine is positive
in quads I and IV, so another answer is 360 - 20.77 ° or 339.23°
BUT, your domain was 0 < x < 180°, so we reject that answer
Going back we see that cosx = -.935
so x must be in quads II and III, but we only need quad II,
so x = 180 - 20.77 ° = 159.23
if you want your answer in radians, set the DRG to RAD
repeat the same steps, but use 2π and π instead of 360° and 180°
cosx = ±√(7/8) = ±0.935
depends on your calculator.
on mine (SHARP) I do the following.
2nd cos
.935
=
to get 20.77...
I have it said on degrees, (the DRG) key, so one answer is 20.77°
Of course using your CAST rule, you know that the cosine is positive
in quads I and IV, so another answer is 360 - 20.77 ° or 339.23°
BUT, your domain was 0 < x < 180°, so we reject that answer
Going back we see that cosx = -.935
so x must be in quads II and III, but we only need quad II,
so x = 180 - 20.77 ° = 159.23
if you want your answer in radians, set the DRG to RAD
repeat the same steps, but use 2π and π instead of 360° and 180°
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