Asked by Raj
Find the value of cos2x=3/4.Find the two values of x.
Answers
Answered by
oobleck
cos2x = 3/4
2cos^2x - 1 = 3/4
2cos^2x = 7/4
cos^2x = 7/8
cosx = ±√(7/8) = ±0.935
...
2cos^2x - 1 = 3/4
2cos^2x = 7/4
cos^2x = 7/8
cosx = ±√(7/8) = ±0.935
...
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