Asked by Leah
Solve initial value problem explicitly:
1. y'= ye^-x, y(0)=1
2. y'= 5xe^-y, y(1)=1
1. y'= ye^-x, y(0)=1
2. y'= 5xe^-y, y(1)=1
Answers
Answered by
MathMate
1. See
http://www.jiskha.com/display.cgi?id=1296694049
2. See
http://www.jiskha.com/display.cgi?id=1296697362
http://www.jiskha.com/display.cgi?id=1296694049
2. See
http://www.jiskha.com/display.cgi?id=1296697362
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